Triangles Class 10 — Theorems, Proofs & Solved Examples

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Triangles Class 10: Theorems, Proofs & Solved Examples (2026 Guide)

📅 Updated Sep 8, 2026 ⏱ 14 min read 📘 CBSE / NCERT Class 10, Chapter 6 ✍️ MyTestSeries Expert Team
Triangles Class 10 — Basic Proportionality Theorem and Pythagoras Theorem explained by MyTestSeries

Triangles is where Class 10 Geometry stops being about single shapes and starts being about relationships between shapes. Two triangles that look completely different in size can still be "the same" in every way that matters mathematically — same angles, proportional sides — and that single idea, similarity, is what this entire chapter is built around.

This guide covers every theorem in the chapter — the Basic Proportionality Theorem, the three similarity criteria, the areas-of-similar-triangles theorem, and the Pythagoras theorem — each with a worked example, followed by the exact mistakes that quietly cost marks: mismatched ratios, forgetting to square a ratio, and misidentifying the hypotenuse.

4Core Theorems
6Solved Examples
6Common Mistakes
1Quick Formula Table
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1. What Makes Triangles Similar?

Similar triangles have exactly the same shape but not necessarily the same size — their corresponding angles are equal, and their corresponding sides are in the same ratio (proportional). This is different from congruent triangles, which are similar triangles with a side ratio of exactly 1:1 — identical in both shape and size.

💡 Quick check: Every equilateral triangle is similar to every other equilateral triangle, regardless of size — all angles are 60°, and the sides are always in equal proportion to each other.

2. Basic Proportionality Theorem (Thales Theorem)

If DE ∥ BC in triangle ABC, with D on AB and E on AC, then: AD/DB = AE/EC Converse: if AD/DB = AE/EC, then DE ∥ BC.

This theorem — and its converse — is one of the most frequently tested ideas in the chapter, because it lets you either find an unknown length once you know a line is parallel to a side, or confirm that a line is parallel just by checking a ratio.

3. Similarity Criteria — AA, SSS, SAS

CriterionCondition
AA (Angle-Angle)Two pairs of corresponding angles are equal (the third pair is automatically equal too)
SSS (Side-Side-Side)All three pairs of corresponding sides are in the same ratio
SAS (Side-Angle-Side)Two pairs of corresponding sides are proportional, and the angle between them is equal
⚠️ Watch out: AA needs two angles, not one. A single equal angle proves nothing about similarity on its own.
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4. Areas of Similar Triangles Theorem

Area(△1) / Area(△2) = (side of △1 / corresponding side of △2)² The area ratio is the square of the side ratio — never the side ratio itself.
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5. Pythagoras Theorem & Its Converse

c² = a² + b²  (c = hypotenuse, the side opposite the right angle) Converse: if c² = a² + b² for the longest side c of a triangle, then the angle opposite c is 90°.

Interestingly, the Class 10 proof of the Pythagoras theorem uses similar triangles: dropping a perpendicular from the right angle to the hypotenuse creates two smaller triangles, both similar to the original — and comparing their side ratios leads directly to c² = a² + b².

6. Six Fully Solved Examples

Example 1 — Basic Proportionality Theorem

In triangle ABC, DE ∥ BC, with AD = 1.5 cm, DB = 3 cm, and AE = 1 cm. Find EC.

By BPT: AD/DB = AE/EC → 1.5/3 = 1/EC → EC = (1 × 3)/1.5 = 2 cm

Example 2 — Converse of BPT

In triangle ABC, AD = 5.7 cm, DB = 9.5 cm, AE = 3.6 cm, and EC = 6 cm. Is DE ∥ BC?

AD/DB = 5.7/9.5 = 0.6, and AE/EC = 3.6/6 = 0.6.
Since the ratios are equal, by the converse of BPT, DE is parallel to BC.

Example 3 — AA Similarity

In triangles ABC and PQR, ∠A = ∠P and ∠B = ∠Q. If AB = 6 cm, BC = 8 cm, and PQ = 3 cm, find QR.

By AA similarity, △ABC ~ △PQR, so corresponding sides are proportional: AB/PQ = BC/QR.
6/3 = 8/QR → QR = (8 × 3)/6 = 4 cm

Example 4 — Areas of Similar Triangles

Two similar triangles have corresponding sides in the ratio 4:9. Find the ratio of their areas.

Area ratio = (side ratio)² = (4/9)² = 16/81

Example 5 — Pythagoras Theorem

The two legs of a right triangle measure 6 cm and 8 cm. Find the hypotenuse.

c² = 6² + 8² = 36 + 64 = 100 → c = √100 = 10 cm

Example 6 — Word problem (ladder, converse application)

A 10 m ladder is placed against a wall so that its foot is 6 m from the base of the wall. How high up the wall does the ladder reach?

The ladder, wall, and ground form a right triangle with the ladder as the hypotenuse.
h² = 10² − 6² = 100 − 36 = 64 → h = √64 = 8 m

7. Common Mistakes Students Make

⚠️ Mistake 1 — Mismatching segments in BPT. Writing AD/AB instead of AD/DB is a common slip — the ratio compares the two parts of the same side, not one part to the whole side.
⚠️ Mistake 2 — Assuming one equal angle proves AA similarity. AA requires two pairs of equal corresponding angles, not one.
⚠️ Mistake 3 — Using SSS/SAS with only two proportional sides checked. SSS needs all three side pairs proportional; SAS needs the included angle specifically, not just any angle.
⚠️ Mistake 4 — Forgetting to square the ratio in the areas theorem. A side ratio of 4:9 gives an area ratio of 16:81, not 4:9 — this squaring step is the single most common miss in this section.
⚠️ Mistake 5 — Misidentifying the hypotenuse. The hypotenuse is always the side opposite the right angle (and the longest side) — plugging the wrong side into c² in the Pythagoras formula gives a wrong answer immediately.
⚠️ Mistake 6 — Confusing "similar" with "congruent." Similar triangles need not have equal sides, only equal angles and proportional sides — don't assume equal areas or equal side lengths unless the ratio is explicitly 1:1.
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8. Quick Formula Recap Table

ConceptFormula / Condition
Basic Proportionality TheoremDE ∥ BC ⟹ AD/DB = AE/EC
AA similarityTwo pairs of equal corresponding angles
SSS similarityAll three pairs of sides proportional
SAS similarityTwo side pairs proportional + included angle equal
Areas of similar trianglesArea ratio = (side ratio)²
Pythagoras Theoremc² = a² + b² (c = hypotenuse)
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9. How to Revise This Chapter Effectively

📖 Draw every triangle problem before solving it. Labelling vertices, marking the parallel line or right angle, and writing known lengths directly on the sketch prevents almost every mismatched-ratio mistake.

✍️ Learn the similarity criteria as a checklist, not a name. Before writing "AA" or "SSS," confirm out loud exactly which angles or sides you've actually verified.

🧮 Practise the areas-of-similar-triangles theorem separately from the side-ratio ones. The squaring step is easy to forget precisely because it looks so similar to the linear BPT ratio.

🎯 For Pythagoras problems, identify the hypotenuse first, before writing any equation. It's always the longest side, opposite the right angle — get this right and the rest is direct substitution.

🔁 Revisit this page before your unit test. Bookmark it, and use the Quick Formula Recap Table (Section 8) as your final five-minute revision before the exam.

10. Frequently Asked Questions

What is the Basic Proportionality Theorem (Thales Theorem)?
If a line is drawn parallel to one side of a triangle, intersecting the other two sides at distinct points, it divides those two sides in the same ratio. The converse also holds: equal ratios imply the line is parallel to the third side.
What are the criteria for similarity of triangles?
AA (two equal corresponding angles), SSS (all three sides proportional), and SAS (two sides proportional with the included angle equal).
What is the theorem on areas of similar triangles?
The ratio of the areas of two similar triangles equals the square of the ratio of their corresponding sides.
What is the Pythagoras Theorem?
In a right triangle, c² = a² + b², where c is the hypotenuse. The converse states that if this relationship holds for the longest side of a triangle, the triangle has a right angle opposite that side.
What is the difference between similar and congruent triangles?
Similar triangles have equal angles and proportional sides but can differ in size. Congruent triangles are similar with a side ratio of exactly 1:1 — identical in shape and size.
What are the most common mistakes in Class 10 Triangles?
Mismatching segments in the BPT ratio, assuming one equal angle proves AA similarity, forgetting to square the ratio in the areas theorem, misidentifying the hypotenuse, and confusing similarity with congruence.

Conclusion: One Idea, Many Theorems

Every theorem in this chapter is really an extension of one idea: proportional relationships between shapes reveal deep structural truths. The Basic Proportionality Theorem, the similarity criteria, the areas theorem, and even the Pythagoras theorem all trace back to comparing ratios carefully and correctly.

Rework the six solved examples above without checking the answers first, sketch every triangle problem before writing an equation, and always double-check which segments or sides actually correspond before applying a ratio. That habit — sketch, label, then calculate — is what turns theorem knowledge into consistent exam marks.

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Tags: Triangles Class 10, Basic Proportionality Theorem, Similar Triangles, AA SSS SAS Similarity, Areas of Similar Triangles, Pythagoras Theorem, CBSE 2026, NCERT Class 10 Maths Chapter 6

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